Charm Bracelet

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 38909		Accepted: 16862

Description

Bessie has gone to the mall's jewelry store and spies a charm bracelet. Of course, she'd like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight W_i (1 ≤ W_i ≤ 400), a 'desirability' factor D_i (1 ≤ D_i ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

Input

* Line 1: Two space-separated integers: N and M * Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: W_i and D_i

Output

* Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

Sample Input

4 61 42 63 122 7

Sample Output

23

Source

题目链接：http://poj.org/problem?id=3624

分析：01背包裸题，顺带敲了一遍，做个复习吧，怕忘了！详解请参看我的博客http://www.cnblogs.com/ECJTUACM-873284962/p/6815610.html，里面有对01背包的完全介绍以及用法！

下面给出AC代码：

1 #include 
      
        2 #include 
       
         3 #include 
        
          4 using namespace std; 5 int w[35000],d[35000],dp[35000]; 6 int main() 7 { 8     int n,m; 9     while(scanf("%d%d",&n,&m)!=EOF)10     {11         for(int i=1;i<=n;i++)12             scanf("%d%d",&w[i],&d[i]);13         for(int i=1;i<=n;i++)14         {15             for(int j=m;j>=w[i];j--)16             {17                 dp[j]=max(dp[j],dp[j-w[i]]+d[i]);18             }19         }20         printf("%d\n",dp[m]);21     }22     return 0;23 }